If we take deuterium/antideuterium, that is total reactant mass of 0.08 kg per second or 59 545 720 kilograms of ultra-dense deuterium and its antimatter equivalent per second.
So we can calculate standard energy output of 7.2 x 10e15 watts or 7.2 PW for standard deuterium or 5.36 x 10e24 W (5 360 000 000 PW) for super-dense deuterium. However, one must note that "standard output" is output during normal subligh operations, i.e. warp drive disengaged, weaponry is not used etc. Maximum output might be as much as ten times greater.
Episode evidence
In "True Q"[TNG6], we hear the following exchange occur in Engineering:
Amanda: "It's hard to imagine how much energy is being harnessed in there."
Data : "Imagination is not necessary; the scale is readily quantifiable. We are presently generating 12.75 billion gigawatts per . . . "
One must understand that gigawatts per anything is actually gigawatts per anything. "Anything" here can stand for volume etc (it can't for mass beacouse, since it is M/AM reaction, energy gained from mass is always E=mc^2).
12.75 billion GW is 1.275 x 10e19 joules per second, which translates into 141.86 kilograms of fuel annihilated. Ultra-dense deuterium has density of 140 kilograms per cubic centimeter. Coincidence? I don't think so.
With that, we can calculate total output of E-D warp core to be 5.84 x 10e24 W or 5.84x10e12 TW (5 840 000 000 000 TW or 5 840 000 000 PW).
As for Star Wars power generation, see here:
http://www.st-v-sw.net/STSWimpower.html
UPDATE: Another possibility is that he was about to say "per pulse", which would lower total power production to 4.25 billion GW. That is equivalent of 1 gigaton per second.
UPDATE 2: In script, Data does say "per second".
On my site.
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